Integral of exponential distribution from zero to infinity

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Homework Help Overview

The discussion revolves around the integration of an exponential distribution function, specifically the integral of the form \( p(x) = A e^{-(x/a)} \) from zero to infinity. Participants are tasked with finding the constant \( A \) that normalizes the integral to 1 and determining the mean \( x \) using a related integral.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the validity of the expression for \( A \) as a function of \( x \) and whether it can be treated as a constant. There are discussions about the integration process and the evaluation of limits at zero and infinity.

Discussion Status

There is an ongoing examination of the assumptions regarding the constants \( A \) and \( a \). Some participants are providing guidance on the integration process, while others are seeking clarification on fundamental concepts related to integration.

Contextual Notes

Some participants express concern that the original poster may not have a solid understanding of integration, suggesting that the problems presented are typical of introductory calculus. There is also a note about the need to evaluate the anti-derivative at the specified limits.

cooper607
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Homework Statement



here's a problem from my assignment

let integral p(x)dx=Ae^-(x/a) dx...(1)
find value of A, that makes integral p(x)dx=1;
and
find mean x so that integral x*p(x)dx=a...2)


Homework Equations


now
to solve the first one i found out A to be (-1/a*e^(x/a))
but when i am integrating the two i can not find that value 1...please tell me if my value of A is ok or not...
and for the second problem how can i integrate those three components all together?
what is the formula, please notify here...
thanks in advance



The Attempt at a Solution


A to be (-1/a*e^(x/a))
 
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hi cooper607! :smile:

you mean [itex][Ae^{-x/a}]_0^{infty}\ =\ 1[/itex]
cooper607 said:
… to solve the first one i found out A to be (-1/a*e^(x/a))

A is supposed to be a constant, how can it be a function of x ? :redface:
 
cooper607 said:

Homework Statement



here's a problem from my assignment

let integral p(x)dx=Ae^-(x/a) dx...(1)
find value of A, that makes integral p(x)dx=1;
and
find mean x so that integral x*p(x)dx=a...2)


Homework Equations


now
to solve the first one i found out A to be (-1/a*e^(x/a))
but when i am integrating the two i can not find that value 1...please tell me if my value of A is ok or not...
and for the second problem how can i integrate those three components all together?
what is the formula, please notify here...
thanks in advance



The Attempt at a Solution


A to be (-1/a*e^(x/a))

No, its not ok. How is it even a value in the first place?
 
cooper607 said:

Homework Statement



here's a problem from my assignment

let integral p(x)dx=Ae^-(x/a) dx...(1)
find value of A, that makes integral p(x)dx=1;
and
find mean x so that integral x*p(x)dx=a...2)


Homework Equations


now
to solve the first one i found out A to be (-1/a*e^(x/a))
but when i am integrating the two i can not find that value 1...please tell me if my value of A is ok or not...
and for the second problem how can i integrate those three components all together?
what is the formula, please notify here...
thanks in advance



The Attempt at a Solution


A to be (-1/a*e^(x/a))

Are A and a supposed to be constants? If so, then why would you equate A to (-1/a*e^(x/a))?

Let me ask a more fundamental question: have you studied integration? Both of the questions you ask are simple integration problems from introductory calculus. However, if you have not yet had that material, it would be understandable that you are having problems.

RGV
 
The title of this thread says that the integral is from 0 to infinity. Did you not evaluate the anti-derivative at those values?
 

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