1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Integral of exponential distribution from zero to infinity

  1. Jun 13, 2012 #1
    1. The problem statement, all variables and given/known data

    here's a problem from my assignment

    let integral p(x)dx=Ae^-(x/a) dx...........(1)
    find value of A, that makes integral p(x)dx=1;
    and
    find mean x so that integral x*p(x)dx=a.........2)


    2. Relevant equations
    now
    to solve the first one i found out A to be (-1/a*e^(x/a))
    but when i am integrating the two i can not find that value 1........plz tell me if my value of A is ok or not........
    and for the second problem how can i integrate those three components all together?
    what is the formula, plz notify here......
    thanks in advance



    3. The attempt at a solution
    A to be (-1/a*e^(x/a))
     
  2. jcsd
  3. Jun 13, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    hi cooper607! :smile:

    you mean [itex][Ae^{-x/a}]_0^{infty}\ =\ 1[/itex]
    A is supposed to be a constant, how can it be a function of x ? :redface:
     
  4. Jun 13, 2012 #3
    No, its not ok. How is it even a value in the first place?
     
  5. Jun 13, 2012 #4

    Ray Vickson

    User Avatar
    Science Advisor
    Homework Helper

    Are A and a supposed to be constants? If so, then why would you equate A to (-1/a*e^(x/a))?

    Let me ask a more fundamental question: have you studied integration? Both of the questions you ask are simple integration problems from introductory calculus. However, if you have not yet had that material, it would be understandable that you are having problems.

    RGV
     
  6. Jun 13, 2012 #5

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    The title of this thread says that the integral is from 0 to infinity. Did you not evaluate the anti-derivative at those values?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Integral of exponential distribution from zero to infinity
Loading...