Integral of (ln(e^x + 1))^(1/3) / (e^x + 1)

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ravenea said:

Homework Statement



Integral of (ln(e^x + 1))^(1/3) / (e^x + 1)
See http://www2.wolframalpha.com/input/?i=integral+of+(ln(e**x+++1))**(1/3)/(e**x+++1)"


Homework Equations



N/A

The Attempt at a Solution



First, substitute k = ln(e^x + 1) dk = dx(e^x)/(e^x + 1)
Then, used integration by parts, but got to a loop...

If you let u = ln(ex+1) show us what you get for your du integral. There should be no x's in it.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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