Integral of trigonometric functions

darkmagic
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Homework Statement



How can I integrate this:

\int sin (nt) sin (n \pi t) dt

This actually in the Fourier series.
 
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Use the trig identity:

\sin\theta\sin\phi=\frac{\cos{(\theta-\phi)}-\cos{(\theta+\phi)}}{2}
 
You can use the following identity:

\sin a \sin b=\frac{\cos(a-b)-\cos(a+b)} 2
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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