Integrate sinx*sqrt(1+((cosx)^2))dx

  • Thread starter Thread starter Maiko
  • Start date Start date
  • Tags Tags
    Integrate
Click For Summary
SUMMARY

The integral of sin(x) * sqrt(1 + (cos(x))^2) dx can be effectively solved using substitution methods. The recommended substitutions include tan(x) = t or u = cos(x), which simplify the integral into a more manageable form. Specifically, using u = cos(x) transforms the integral into -∫ sqrt(1 + u^2) du, a standard integral that can be solved using known techniques. WolframAlpha can also provide a complete solution for verification.

PREREQUISITES
  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with trigonometric identities and substitutions.
  • Knowledge of standard integrals, particularly involving square roots and trigonometric functions.
  • Experience with computational tools like WolframAlpha for verifying solutions.
NEXT STEPS
  • Study the method of integration by parts in detail.
  • Learn about trigonometric substitutions in integrals, focusing on tan(x) and cos(x).
  • Explore the integral of sqrt(1 + u^2) and its applications.
  • Practice using WolframAlpha for solving complex integrals and verifying results.
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for effective methods to teach integral calculus concepts.

Maiko
Messages
2
Reaction score
0

Homework Statement


Integrate sinx*sqrt(1+((cosx)^2))dx


Homework Equations


integral udv = uv - integral vdu


The Attempt at a Solution


I tried integration by parts which is: integral udv = uv - integral vdu
I tried substituting (cosx)^2= 1-(sonx)^2
neither of them seemed to work...
 
Physics news on Phys.org
Oops, bad advice. Sorry
 
Hi, the your integrated is resolved by wolframalpha.com.
Here's the image:

<< Complete solution removed by Hootenanny >>[/color]
 
Use the substitution tan(x) = t

sin^2(x)=\frac{tan^2(x)}{1+tan^2(x)}=\frac{t^2}{1+t^2}

cos^2(x)=\frac{1}{1+tan^2(x)}=\frac{1}{1+t^2}

dx=\frac{dt}{1+t^2}

Or even better, you can use the substitution cos(x)=t
 
You could also use the substitution u = cosx. Then your integral turns into - \int \sqrt[]{1+u^2} du.

Do you recognize this integral now?
 

Similar threads

Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
16
Views
3K