I need to integrate this indefinite integral: 1/(x-6)^2 dx(adsbygoogle = window.adsbygoogle || []).push({});

Here is my work...

Let u= x-6

du/dx=1

so: integral 1/u^2 du

= 3/u^3 + c (constant)

=3/(x-6)^3 + c

Have I gone wrong? And if so where? Thanks

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# Integrate this indefinite integral: 1/(x-6)^2 dx

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