Integrating a Spherical Coordinate Problem

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SUMMARY

The discussion focuses on evaluating the integral of the function \(8 - x^2 - y^2\) over a solid hemisphere defined by the equation \(x^2 + y^2 + z^2 \leq 9\) and \(z \leq 0\). The integral is set up in spherical coordinates, with the limits of integration specified as \(0\) to \(2\pi\) for \(\theta\), \(\frac{\pi}{2}\) to \(\pi\) for \(\phi\), and \(0\) to \(3\) for \(p\). The correct transformation from Cartesian to spherical coordinates is confirmed, ensuring that \(x^2 + y^2\) simplifies to \(\rho^2 \sin^2(\phi)\). The integral setup is validated, affirming the approach taken by the user.

PREREQUISITES
  • Spherical coordinates transformation
  • Understanding of triple integrals
  • Knowledge of solid geometry, specifically hemispheres
  • Familiarity with polar coordinate equations
NEXT STEPS
  • Study the derivation of spherical coordinate transformations
  • Practice evaluating triple integrals in spherical coordinates
  • Explore applications of solid integrals in physics and engineering
  • Learn about the properties of hemispherical volumes
USEFUL FOR

Students in calculus or advanced mathematics, educators teaching integral calculus, and anyone interested in applications of spherical coordinates in mathematical analysis.

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Homework Statement



Evaluate the integral below, where H is the solid hemisphere x^2 + y^2 + z^2 ≤ 9, z ≤ 0

\iiint 8-x^2-y^2\,dx\,dy\,dz.

Homework Equations



none

The Attempt at a Solution



\int_{0}^{2\pi} \int_{\frac{\pi}{2}}^{\pi} \int_{0}^{3} (8-2p^2 \sin^2{\phi}) p^2 \sin{\phi}\ ,dp\,d\phi\, d\theta

do I set up the integral right?
 
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In polar coordinates x= \rho cos(\theta)sin(\phi) and y= \rho sin(\theta)sin(\phi) so
x^2+ y^2= \rho^2 cos^2(\theta) sin^2(\phi)+ \rho^2 sin^2(\theta) sin^2(\phi)
= \rho^2 sin^2(\phi)(cos^2(\theta)+ sin^2(\theta))= \rho^2 sin^2(\phi)
NOT "2\rho^2 sin^2(\phi).
 
ye! sorry. 8-p^2*sin^2(phi)

but if I use = \rho^2 sin^2(\phi) are the limit of this integral right for the question stated above.
 

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