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meee
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help me integrate this please
sqroot( kx + (1/4)(k^2) ) dx
i wud like to know whether its solvable? and how to do it?
sqroot( kx + (1/4)(k^2) ) dx
i wud like to know whether its solvable? and how to do it?
Last edited:
The formula for integrating sqroot(kx + (1/4)(k^2)) using basic integration techniques is: ∫√(kx + (1/4)(k^2)) dx = (2/3k)(kx + (1/4)(k^2))^3/2 + C
The basic integration techniques used to solve sqroot(kx + (1/4)(k^2)) are substitution, integration by parts, and trigonometric substitution.
Yes, sqroot(kx + (1/4)(k^2)) can be solved using u-substitution. In this case, u = kx + (1/4)(k^2) and du = kdx.
The power rule for integration states that ∫x^n dx = (1/(n+1))x^(n+1) + C, where n is any real number except -1.
Yes, trigonometric substitution can be used to solve sqroot(kx + (1/4)(k^2)) by using the substitution u = √(kx + (1/4)(k^2)) and then applying the appropriate trigonometric identities to simplify the integral.