Integrating the function sqrt(1-sin2x)

rwx1606
Messages
31
Reaction score
0

Homework Statement


Integrate the following \int\sqrt{1-sin2x} dx


Homework Equations


sin2x=2cosxsinx
cos2x= cos^2 (x) -sin^2 (x)


The Attempt at a Solution


I've rearranged the integral so its 1-sin2x/\sqrt{1-sin2x} but other than that I've just been randomly trying stuff. Any hints on where to begin?
 
Physics news on Phys.org
Try using the fact that \cos^2 x + \sin^2 x =1
 
still not getting anywhere.i tried multiplying top and bottom by 1-sin2x. And then using what you said I got a cos^2(2x) over an ugly thing.
 
\int\sqrt{\cos^2 x - 2 \sin x \cos x + \sin^2 x}dx

Simplify!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top