Integrating to determine speed as a function of time

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Homework Help Overview

The discussion revolves around integrating to determine speed as a function of time, specifically in the context of an object experiencing a resistive force upon landing. The subject area includes dynamics and the application of Newton's second law.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the relationship between force and velocity. Questions arise regarding the interpretation of the equations and the implications of integrating the velocity function.

Discussion Status

Some participants have provided insights into the equations involved and the process of integration. There is an ongoing exploration of the implications of the integration and the resulting expressions for velocity.

Contextual Notes

Participants are navigating through the initial conditions and the specific resistive forces acting on the object, which may not be fully defined in the original problem statement.

AryRezvani
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Homework Statement



2lk90kw.jpg


Homework Equations



The above formulas

The Attempt at a Solution



I'm lost on where to start with this. The object has an intial velocity in the X direction and has the resistive force of the plontons acting upon it when it lands. What exactly is the equation located in the problem?
 
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Hi AryRezvani! :smile:
AryRezvani said:
What exactly is the equation located in the problem?

That's good ol' Newton's second law, F = ma

F = -bv, ma = mdv/dt, so mdv/dt = bv, so dv/v = -b/m dt :wink:

(the "m =" appears to be a misprint)
 
tiny-tim said:
Hi AryRezvani! :smile:That's good ol' Newton's second law, F = ma

F = -bv, ma = mdv/dt, so mdv/dt = bv, so dv/v = -b/m dt :wink:

(the "m =" appears to be a misprint)

Thanks for the response Tiny-Tim :)

Okay, so i follow you somewhat. F = -bv (general formula for resistive force).

According to Newton's second law, F=ma which can be rewritten as F=m(dv/dt).

You then equate those two, and you get m(dv/dt)=-bv.

What happens after this? (dv/v) is the derivative of velocity with respect to velocity? :eek:
 
AryRezvani said:
(dv/v) is the derivative of velocity with respect to velocity? :eek:

ah, no …

∫ dv/v is a short way of writing ∫ (1/v) dv …

just integrate it! :smile:
 
Ohh so when you integrate that you get ln(v)?
 
AryRezvani said:
Ohh so when you integrate that you get ln(v)?

yes! :smile:

(to be precise, ln(v) - ln(vo))
 

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