Integrating to determine speed as a function of time

AI Thread Summary
The discussion focuses on integrating to determine speed as a function of time, specifically using Newton's second law, F = ma. Participants clarify the relationship between resistive force and acceleration, leading to the equation m(dv/dt) = -bv. The integration of dv/v is discussed, with the result being ln(v) - ln(vo), indicating how to express velocity in terms of time. The conversation emphasizes the importance of understanding the integration process in solving the problem. Overall, the thread provides insights into applying physics principles to analyze motion under resistive forces.
AryRezvani
Messages
65
Reaction score
0

Homework Statement



2lk90kw.jpg


Homework Equations



The above formulas

The Attempt at a Solution



I'm lost on where to start with this. The object has an intial velocity in the X direction and has the resistive force of the plontons acting upon it when it lands. What exactly is the equation located in the problem?
 
Physics news on Phys.org
Hi AryRezvani! :smile:
AryRezvani said:
What exactly is the equation located in the problem?

That's good ol' Newton's second law, F = ma

F = -bv, ma = mdv/dt, so mdv/dt = bv, so dv/v = -b/m dt :wink:

(the "m =" appears to be a misprint)
 
tiny-tim said:
Hi AryRezvani! :smile:That's good ol' Newton's second law, F = ma

F = -bv, ma = mdv/dt, so mdv/dt = bv, so dv/v = -b/m dt :wink:

(the "m =" appears to be a misprint)

Thanks for the response Tiny-Tim :)

Okay, so i follow you somewhat. F = -bv (general formula for resistive force).

According to Newton's second law, F=ma which can be rewritten as F=m(dv/dt).

You then equate those two, and you get m(dv/dt)=-bv.

What happens after this? (dv/v) is the derivative of velocity with respect to velocity? :eek:
 
AryRezvani said:
(dv/v) is the derivative of velocity with respect to velocity? :eek:

ah, no …

∫ dv/v is a short way of writing ∫ (1/v) dv …

just integrate it! :smile:
 
Ohh so when you integrate that you get ln(v)?
 
AryRezvani said:
Ohh so when you integrate that you get ln(v)?

yes! :smile:

(to be precise, ln(v) - ln(vo))
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top