Integrating until symmetric bilinear form

TheFerruccio
Messages
216
Reaction score
0

Homework Statement


I am looking for some quick methods to integrate while leaving each step in its vector form without drilling down into component-wise integration, and I am wondering whether it is possible here.

Suppose I have a square domain over which I am integrating two functions w and v. Using integration by parts, what steps can I use to ensure that I end up with a symmetric blinear form + boundary terms?

Homework Equations



##\exists## a region ##\Omega## enclosed by ##\Gamma## and on ##\Omega## $$\int_\Omega{Tv\nabla^2 w d\Omega}=\int_\Omega{v p(x,y) d\Omega}$$

The Attempt at a Solution


Using integration by parts, whereby I feel as if I am completely guessing here:
$$T\left[v\nabla w\right]_\Gamma-T\int_\Omega{\nabla v \cdot \nabla w dV} = \int_\Omega{v p(x,y) d\Omega}$$

Is this the correct symmetric bilinear form that I am looking for? How would that simplified boundary term expression be evaluated explicitly?
 
Unfortunately not. I have come to the conclusion that there is no one here who knows this particular material. It is a blend of math and engineering and computation. I will update the threads with solutions once I find them. I eventually do, but I have never gotten a single question of this area of material answered on these forums, which is a first.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top