Integrating with Fractions: Understanding the Solution for (x^2 - 2x)/2

omf24
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Can someone please help me with this problem. Please see the attached image.

The integration when removing the min and max is also provided, how is the answer x2/2 - x3/6? Do we not do anything with the 1 - 1/2 part? and the +2 part? Are we only looking at (x2-2x)/2?

I appreciate the help.
 

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The integrand is x - x2/2.
 
-\frac{1}{2}\left(x^2- 2x+ 2\right)= -\frac{1}{2}x^2+ x- 1
Adding 1 to that gives the integrand
-\frac{1}{2}x^2+ x
as mathman says.
 
Thanks, that is exactly what I needed to know.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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