Integrating with Trigonometric Substitution: Solving ∫ x √ 4 + x2 dx

bengaltiger14
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Homework Statement



Evaluate ∫ x √ 4 + x2 dx by using the trigonometric substitution x = 2tanθ

I am starting on the right track by subbing x=2tanθ into x like this:


=∫ 2tanθ √ 4 + 2tanθ(2)

then, do I just integrate that for the correct answer?
 
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Just to clear up, are you integrating this:

\int \frac{xdx}{\sqrt{4+x^2}}

or this:

\int x(\sqrt{4+x^2})dx

Either way you'll have to put dx in terms of d\theta[/tex] and then use a trig identity to simplify the whole integral.
 
\int x(\sqrt{4+x^2})dx
 
Ok, well as I said before, can you write dx in terms of d\theta and substitute for the x's? Thats probably the first step.
 
If the question requires you to do this integral by trig substitution, then, as Kurdt has said, you have forgotten to change the dx.

If the question allows you to use any method, then tig substitution is not the best method; a different substitution is better. In fact, this integral is simple enough that, after seeing a few more examples of this type, you should be able to write down the answer by inspection.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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