Integration by Parts: Solve Integral of (1-x)

matematikuvol
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Homework Statement


Solve integral
\int^{1}_0(1-x)\frac{d}{dx}\frac{\sin Cx}{C}dx

Homework Equations



\int udv=uv-\int vdu



The Attempt at a Solution



u=1-x

dv=\frac{d}{dx}\frac{\sin Cx}{C}dx

What is v?

How to integrate

\frac{d}{dx}\frac{\sin Cx}{C}dx?
 
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matematikuvol said:

Homework Statement


Solve integral
\int^{1}_0(1-x)\frac{d}{dx}\frac{\sin Cx}{C}dx

Homework Equations



\int udv=uv-\int vdu



The Attempt at a Solution



u=1-x

dv=\frac{d}{dx}\frac{\sin Cx}{C}dx

What is v?

How to integrate

\frac{d}{dx}\frac{\sin Cx}{C}dx?

Is C a constant?

Why not just differentiate sin(Cx)/C?
 
matematikuvol said:
How to integrate

\frac{d}{dx}\frac{\sin Cx}{C}dx?

What is the anti-derivative of a derivative?
 
Fundamental Theorem of Calculus!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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