Integration by Parts: Solving Integrals with √(1+x^2) and x

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SUMMARY

The discussion focuses on solving the integral ∫ √(1+x^2) dx using integration by parts. The chosen functions are f(x) = √(1+x^2) and g'(x) = 1, leading to the equation ∫ √(1+x^2) * 1 dx = x * √(1+x^2) - ∫ x^2 * 1/√(1+x^2) dx. Further simplification reveals that x^2/√(1+x^2) can be expressed as √(1+x^2) - 1/√(1+x^2), aiding in the integration process. This method effectively breaks down the integral into manageable components for easier evaluation.

PREREQUISITES
  • Understanding of integration by parts formula: ∫ f(x) g'(x) dx = f(x) g(x) - ∫ f '(x) g(x) dx
  • Knowledge of derivatives, specifically f '(x) = x * 1/√(1+x^2)
  • Familiarity with algebraic manipulation of square roots and fractions
  • Basic calculus concepts, including definite and indefinite integrals
NEXT STEPS
  • Practice additional integration by parts problems using different functions
  • Explore advanced techniques in integration, such as trigonometric substitution
  • Learn about the properties of integrals involving square roots and rational functions
  • Study the application of integration by parts in solving real-world problems
USEFUL FOR

Students studying calculus, mathematics educators, and anyone seeking to enhance their skills in solving integrals using integration techniques.

Chris Fernandes
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Homework Statement


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Homework Equations


∫ f(x) g'(x) dx = f(x) g(x) - ∫ f '(x) g(x) dx

f(x)=√(1+x^2)
f '(x)=x * 1/√(1+x^2)

g'(x)=1
g(x)=x

The Attempt at a Solution


∫ √(1+x^2) * 1 dx
=x * √(1+x^2) - ∫ x^2 * 1/√(1+x^2) dx

Further integration just makes the result look further from what it's supposed to look like
 
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Chris Fernandes said:
=x * √(1+x^2) - ∫ x^2 * 1/√(1+x^2) dx
The latter part may help to go to your answer. You maybe can try to make it become ##\frac{x^2}{\sqrt{1+x^2}}=\sqrt{1+x^2}-\frac{1}{\sqrt{1+x^2}}.##
 
tommyxu3 said:
The latter part may help to go to your answer. You maybe can try to make it become ##\frac{x^2}{\sqrt{1+x^2}}=\sqrt{1+x^2}-\frac{1}{\sqrt{1+x^2}}.##

Thank you!
 

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