Integration by substitution indefinite integral 5

[char808]

Homework Statement

indefinite integral 5\picos\pit

Homework Equations

The Attempt at a Solution

5\pi int cos\pit

Substitution Method

5\pi x sin (1/\pit

 

[Mark44]

Homework Statement

indefinite integral 5\picos\pit

Homework Equations

The Attempt at a Solution

5\pi int cos\pit

Substitution Method

5\pi x sin (1/\pit

Is this your integral?
\int 5 \pi cos(\pi t)dt
Click the integral above to see how the LaTeX looks.

A reasonable substitution would be u = \pi t, so du = \pi dt.
Can you take it from there?

 

[char808]

<br /> 5 \pi sin(u)du<br /> <br />

<br /> <br /> 5 \pi sin(u) x du/ \pi<br /> <br />

<br /> <br /> 5sin(\pi t)<br /> <br />

 

[Mark44]

What is the first line supposed to mean?
How did you get from the first line to the second?
How did you get from the second line to the third?
Are any of these expressions related to each other in any way?
Since this is an integration problem, one would think there should be an integral sign somewhere.