- #1
elitespart
- 95
- 0
The loop 9y^2=x(3-x)^2 is revolved about the y-axis. Find the area of the surface generated this way.
I just need help with integration:
[tex]4\pi\int x\sqrt{\frac{x^{2}+2x+1}{4x}}[/tex]
I know I can pull out the 4 but after that I'm lost. Any suggestions?
I just need help with integration:
[tex]4\pi\int x\sqrt{\frac{x^{2}+2x+1}{4x}}[/tex]
I know I can pull out the 4 but after that I'm lost. Any suggestions?