Integration of 1/x^2 sqrt(16-x) with substitution

[teng125]

my question is integra 1 / x^2 sqr root(16-x^2)
i use x = 4 sin y
then i got to integrate 1/16 times [1/(sin y)^2] in which i got stuck.pls help...how do i continue from there as i not sure ow to integra 1/(siny^2

 

[HallsofIvy]

\frac{1}{sin^2y}= csc^2y- you should know the integral for that. What is the derivative of cot y?

(Sorry- I had left out a "}")

 

[Jameson]

Since I can't see Halls' Latex image, he was saying that \int \csc^2(y)dy is very simple, noting that what the derivative of cot(y) is.

 

[benorin]

Ivy's image is: \frac{1}{sin^2y}= csc^2y