Integration of hyperbolic functions

Agent M27
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Homework Statement



\int cosh(2x)sinh^{2}(2x)dx

Homework Equations



Not sure

The Attempt at a Solution



This was an example problem in the book and was curious how they got to the following answer:

\int cosh(2x)sinh^{2}(2x)dx = \frac{1}{2}\int sinh^{2}(2x)2cosh(2x) dx

= \frac{sinh^{3}2x}{6} + C

My issue with this problem is I don't understand what happened to the 2cosh(2x). It relates to sinh^{2}(x)+cosh^{2}(x) but that only equals 1 in normal trig, not hyperbolic. Thanks in advance.

Joe
 
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Agent M27 said:

Homework Statement



\int cosh(2x)sinh^{2}(2x)dx

Homework Equations



Not sure
Hyperbolic trig identities would be very relevant.
Agent M27 said:

The Attempt at a Solution



This was an example problem in the book and was curious how they got to the following answer:
For some reason, your LaTeX wasn't showing up correctly. I fixed it by removing several pairs of [ tex] and [ /tex] tags.
Tip: Use one pair of these tags per block.
Agent M27 said:
\int cosh(2x)sinh^{2}(2x)dx = \frac{1}{2}\int sinh^{2}(2x)2cosh(2x) dx<br /> <br /> = \frac{1}{2}\frac{sinh^{3}2x}{3} + C

My issue with this problem is I don't understand what happened to the 2cosh(2x). It relates to sinh^{2}(x)+cosh^{2}(x) but that only equals 1 in normal trig, not hyperbolic. Thanks in advance.

Joe

The integration was done using an ordinary substitution, u = sinh(2x).
 
Ya I just realized that if I set u= sinh(2x) then du=2cosh(2x) dx then substitute from there. Thanks

Joe
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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