Agent M27
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Homework Statement
\int cosh(2x)sinh^{2}(2x)dx
Homework Equations
Not sure
The Attempt at a Solution
This was an example problem in the book and was curious how they got to the following answer:
\int cosh(2x)sinh^{2}(2x)dx = \frac{1}{2}\int sinh^{2}(2x)2cosh(2x) dx
= \frac{sinh^{3}2x}{6} + C
My issue with this problem is I don't understand what happened to the 2cosh(2x). It relates to sinh^{2}(x)+cosh^{2}(x) but that only equals 1 in normal trig, not hyperbolic. Thanks in advance.
Joe
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