Integrating Gravitational Attraction in n Dimensions

Taylor Smith
Messages
1
Reaction score
0

Homework Statement


I'm working on a generalization of gravitation to n dimensions. I'm trying to compute gravitational attraction experienced by a point mass y due to a uniform mass distribution throughout a ball of radius a -- B(0, a).

Homework Equations



3. The Attempt at a Solution [/B]

I've determined an integral that expresses this problem, (ignoring the constants outside the integral) but I'm unsure how to evaluate it.

I have $$A = \int_{B(0,a)} \frac{x - y}{||x - y||^n} dvol_n(x)$$
I believe this can be expressed as a function of x_n, thus I've further simplified to
$$A = \int_{B(0,a)} \frac{x_n - r}{||x - re_n||^n} dvol_n(x)$$
where $r$ is the norm of y, and e_n is the unit vector that is 0 in all but the nth position. I'm unsure how to proceed with this integral. I'm trying to express it in terms of only a and r.
 
Physics news on Phys.org
What is y (and similar r) and why does A do not depend on it?
I would split the integral in three parts:
- radial direction
- angle between x and the nth direction
- all other directions

3 dimensions are the first where these integrals are all meaningful, so it might be useful to study this case first and then generalize this.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top