Integration: Rationalizing and then Partial Fractions

mickellowery
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Homework Statement


\int\frac{e^xcos(log_7(e^x+9))}{(e^x+9)ln(7)}dx


Homework Equations





The Attempt at a Solution


Let u= (ex+9)
du= exdx
New integral \int\frac{cos(log_7(u))}{(u)ln(7)}du
This is where I got l little lost. Should I let log7(u)=\frac{ln(u)}{ln(7)}? Or is this just a waste of time. I was thinking after that I would use log rules to make it ln(u)-ln(7) and then split it into two separate integrals and follow that by partial fractions. I'm just curious if I'm on the right track.
 
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Just let t=\log_7 u. Then only constant times integral of cosine is left.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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