- #1
char808
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My apologies. I'm not proficient with latex, and it is bogging my computer down for some reason today.
intdx/\sqrt{(4-x^2)} [0, 2/sqrt{2}
Trig Identity: a^2-a^2sin^2\theta
In the interest of my own sanity I am going to leave out the limits of integration, assume they are there. Can someone explain how I input them in latex?
x=2sin\theta
\int dx/\sqrt{4-2sin\theta}
\int dx/\sqrt{4cos^2\theta
\int dx/2cos\theta
1/2 \int dx/cos\theta
1/2ln |sec\theta + tan\theta|
New Limits will be restricted to [-pi/2, pi/2]
I know when I use the identity that changes the limits, but I'm not sure how to calculate them..I assumed since the substitution corresponding to the identity only works on that interval than those would be the new limits.
Homework Statement
intdx/\sqrt{(4-x^2)} [0, 2/sqrt{2}
Homework Equations
Trig Identity: a^2-a^2sin^2\theta
The Attempt at a Solution
In the interest of my own sanity I am going to leave out the limits of integration, assume they are there. Can someone explain how I input them in latex?
x=2sin\theta
\int dx/\sqrt{4-2sin\theta}
\int dx/\sqrt{4cos^2\theta
\int dx/2cos\theta
1/2 \int dx/cos\theta
1/2ln |sec\theta + tan\theta|
New Limits will be restricted to [-pi/2, pi/2]
I know when I use the identity that changes the limits, but I'm not sure how to calculate them..I assumed since the substitution corresponding to the identity only works on that interval than those would be the new limits.
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