Intensity of polaroids at an angle

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To reduce the intensity of unpolarized light by an additional factor of 7 after passing through the first Polaroid, the relationship I2 = (1/7) I1 must be used, where I1 is the intensity after the first Polaroid. The first Polaroid halves the intensity, leading to I1 = 0.5 I0. The second Polaroid's intensity can be expressed as I2 = I1(cos theta)^2, which requires solving for the angle theta. The initial calculation of theta as 32 degrees is deemed incorrect, indicating a misunderstanding in the approach to the problem. Clarification on the correct procedure is sought to accurately determine the angle for the desired intensity reduction.
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Homework Statement


At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light by an additional factor (after the first Polaroid cuts it in half) of 7? b) 25? c) 250?

Homework Equations



The first polaroid decreases the intensity by 1/2, so that's I1 = 0.5I0.
I also have I2 = I1(cos theta)^2.

The Attempt at a Solution



I think it might just be the wording that's getting me, but here's my interpretation:

In the first polaroid, 1/2 the intensity is removed. That makes I1 equal to 0.5 I0.
In the second polaroid, 1/7 of I0 is removed. That makes I2 = 0.5I0 - (1/7 I0), or 5/14 I0.

So then I've got I2 = I1(cos theta)^2 --> 5/14 I0 = 0.5 I0 cos(theta)^2. This gives me 32 as theta, which is incorrect. I haven't tried to work out the rest as there seems to be something wrong with my procedure and they're all essentially the same problem.

Any help is much appreciated!
 
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To reduce I1 by a factor of 7 means that

I2 = (1/7) I1
 
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