Internal explosion, kinetic energy prob

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SUMMARY

The discussion focuses on solving a physics problem involving an internal explosion that separates an object into two pieces with a mass ratio of 1.5:1. Given that 7500 J of energy is released during the explosion, the kinetic energy acquired by each piece must be calculated. The conservation of linear momentum and the relationship between kinetic energy and mass are crucial for solving this problem. The relevant equations include the conservation of momentum and the kinetic energy formula, which are essential for determining the final velocities and energies of the two fragments.

PREREQUISITES
  • Understanding of conservation of momentum principles
  • Familiarity with kinetic energy equations
  • Basic knowledge of mass-energy relationships
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the principles of conservation of momentum in explosions
  • Learn how to apply kinetic energy formulas in collision scenarios
  • Explore mass-energy equivalence and its implications in physics
  • Practice solving similar problems involving energy distribution in explosions
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of explosive events and energy transfer in physical systems.

pb23me
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Homework Statement


an internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.5 times the mass of the other. If 7500 J were released in the explosion, how much kinetic energy did each piece acquire.


Homework Equations


mgyi+1/2mvi2=mgyf+1/2mvf2


The Attempt at a Solution

not to sure how to go about solving this one..
 
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You don't need that (mgy). Energy released in the explosion will go into kinetic energy of two pieces. And will linear momentum be conserved in this case? if so, use this fact.
 
ok well understand that m1v+m2v=m1vf+m2
and KE=p2/2m ... but i just can't figure out how to put this together with the information that I am given.
 

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