- #1
Logarythmic
- 281
- 0
I have showed that if the integrand [tex]f[/tex] in the variational problem
[tex]\delta (\int f dx ) = 0[/tex]
does not depend explicitly on the independent variable x, i.e. satisfies [tex]f = f(y, \dot{y})[/tex], then the Euler equation can be integrated to
[tex]\dot{y} \frac{\partial f}{\partial \dot{y}} - f = const.[/tex]
How can I give an interpretation of this constant for the case that [tex] f = L[/tex] is the Lagrangian and [tex]x = t[/tex] is the time?
[tex]\delta (\int f dx ) = 0[/tex]
does not depend explicitly on the independent variable x, i.e. satisfies [tex]f = f(y, \dot{y})[/tex], then the Euler equation can be integrated to
[tex]\dot{y} \frac{\partial f}{\partial \dot{y}} - f = const.[/tex]
How can I give an interpretation of this constant for the case that [tex] f = L[/tex] is the Lagrangian and [tex]x = t[/tex] is the time?