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Ionic equations and Spectator Ions

  • Thread starter amd123
  • Start date
110
0
This is my reaction
Pb(NO3)2(aq) + H2SO4(aq) → PbSO4(s) + HNO3(aq)
Pb + (NO3)2(aq) + H2 + SO4(aq) → PbSO4(s) + H + NO3(aq)

So far I've done that, and now I'm stuck I see h2 and h and NO3 2 molecules and on the left side i see only one NO3 molecule on the right, can I cross out both or do i have to balance right now? My teacher said you can balance at the end. Can i cross out one h on the left and the remaining on the right? What about NO3?
 

Answers and Replies

110
0
bump?
 
1,899
45
This is my reaction
Pb(NO3)2(aq) + H2SO4(aq) → PbSO4(s) + HNO3(aq)
Ok.
Pb + (NO3)2(aq) + H2 + SO4(aq) → PbSO4(s) + H + NO3(aq)
What is this? (NO3)2, SO4, NO3, don't exist free.
 

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