Is Double Integration Always Necessary for Finding an Object's Center?

  • Thread starter Thread starter Quadruple Bypass
  • Start date Start date
Quadruple Bypass
Messages
120
Reaction score
0
will double integration always help you find where the center of an object is?

another q...what is the difference between the center of mass and centroid?
 
Physics news on Phys.org
Double integration will help you find the center of mass of a laminar object (i.e. a 2-d object, or something roughly 2-d, e.g. a piece of paper). Also, the difference between the center of mass and centroid is the center of mass of an object accounts for variations in desity (mass per unit volume) at different points within an object whereas a centeroid is a purely geometric calculation, and as such only accounts for volume of an object, not mass.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top