Is it possible to work out the centre of an ellipse?

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The discussion revolves around calculating the eccentric angle of the ellipse defined by the equation x² + 9y² = 13 at the point (2,1). It is clarified that the ellipse is centered at the origin, and the eccentric angle is the angle between the x-axis and the line connecting the origin to the point (2,1). Participants note that the calculation of the eccentric angle is more complex than simply using arctan(y/x), as it requires consideration of the ellipse's axes. There is some confusion regarding the angle measurement, but resources are shared to aid understanding. The conversation emphasizes the importance of correctly applying the properties of ellipses in such calculations.
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Is it possible to work out the centre of an ellipse?
The question asks for the eccentric angle of the ellipse with the equation x²+9y²=13 at point (2,1)...
I have no idea how to get this, I know that the angle would be arctan(1/2) if the ellipse was centred at (0,0)

Thanks
 
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But the ellipse IS centered at the origin. It asks for the eccentric angle between the x-axis and the line joining (0,0) and (2,1).

edit: PS: The eccentric angle is not simply arctan(y/x), you have to take the axes of the ellipse into account too!

- Kamataat
 
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Kamataat said:
But the ellipse IS centered at the origin. It asks for the eccentric angle between the x-axis and the line joining (0,0) and (2,1).

edit: PS: The eccentric angle is not simply arctan(y/x), you have to take the axes of the ellipse into account too!

- Kamataat
I am somewhat confused. Surely the line joining (0,0) and (2,1) makes arctan (.5) of an angle with the x axis.:confused:
 
Thanks a lot :biggrin:
 
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