Is Span{W} a Subspace of Vector Space V?

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SUMMARY

The discussion centers on proving that Span{W} is a subspace of vector space V, where W is a subset of V containing n vectors. To establish this, one must demonstrate closure under addition and scalar multiplication. The span is defined as the set of all linear combinations of the vectors in W, represented as S = c1*w1 + c2*w2 + ... + cn*wn and T = k1*w1 + k2*w2 + ... + kn*wn. The participants conclude that both S + T and a*S remain within V, confirming that Span{W} is indeed a subspace.

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Homework Statement

Suppose V is a vector space with operations + and * (under the usual operations) and W = {w1, w2, ... , wn} is a subset of V with n vectors. Show Span{W} is a subspace of V.



The attempt at a solution

I know that to show a set is a subspace, we need to show closure under addition and multiplication. I don't where to go from there. Any suggestions?
 
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Maybe start by reviewing what Span{W} means. Quote the definition in your next post, ok?
 
Start with multiplication.

Span W = c*a*w1+...+c*an*wn

Does this exist in V?

For addition, add Span W to Span R or whatever you want to call it.
 
Dick said:
Maybe start by reviewing what Span{W} means. Quote the definition in your next post, ok?



Dustinsfl said:
Start with multiplication.

Span W = c*a*w1+...+c*an*wn

Does this exist in V?

For addition, add Span W to Span R or whatever you want to call it.


The span is basically the set of all linear combinations of the vectors w1, w2, ... , wn. So then, I can define some vector S and some vector T in terms of w's:

S = c1*w1 + c2*w2 + ... + cn*wn

T = k1*w1 + k2*w2 + ... + kn*wn

I think I get it now. I can see how S + T will be closed, and some constant a*S will be closed.
 

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