Is T=F * r Acceptable for Measuring Torque?

  • Thread starter Thread starter Harmony
  • Start date Start date
AI Thread Summary
The discussion centers on the equation for torque, emphasizing that T = r x F is the correct representation, while T = F * r is deemed unacceptable due to the properties of the cross product. The anticommutative nature of the cross product means that r x F is not equivalent to F x r. Participants highlight the importance of distinguishing between torque and energy units, noting that torque is measured in Newton-meters, while energy is in joules. Some argue that using "meter-Newton" can help clarify this distinction for beginners, despite it not being standard SI terminology. Understanding these differences is crucial for accurately measuring and applying torque in physics.
Harmony
Messages
201
Reaction score
0
I saw in my reference book that T=r * F , and T=F * r is unacceptable. Why is the latter unacceptable?
 
Physics news on Phys.org
Last edited:
Also, the book probably doesn't want you to confuse units of torque (meter*Newtons) and units of energy (Newton*meters). Get in the habit of putting the distance first, as it will help you with the cross products
 
turdferguson said:
Also, the book probably doesn't want you to confuse units of torque (meter*Newtons) and units of energy (Newton*meters).

Huh? The (standard) unit of torque is the Newton-metre; I've never heard of it being called a metre-Newton! Besides, clearly the units Newton and metre commute.

(http://en.wikipedia.org/wiki/Newton_metre)
 
Last edited:
If the unit of torque is the Newton-meter, that implies that its the same as a joule. By using the term "meter-Newton", you can easily differentiate between torque and energy. Even though you just informed me that its not technically SI, it makes more sense to me and probably to someone just starting out
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top