Is the author integrating constants?

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    Constants Integrating
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Discussion Overview

The discussion revolves around the integration of constants in the context of calculating a velocity profile for annular flow. Participants are examining the mathematical steps involved in the integration process and the treatment of the constant R within logarithmic expressions.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • Peter questions the integration of the constant R and its placement within the logarithmic expression.
  • One participant suggests a change of variables to clarify the integration process, asserting that R is not integrated but rather factored out, resulting in R^2 and ln(r/R).
  • Another participant argues that the integration is performed correctly and emphasizes the importance of boundary conditions to determine the integration constant C2.
  • A different viewpoint highlights that R can be multiplied and divided before integration, leading to a correct interpretation of the logarithmic derivative.

Areas of Agreement / Disagreement

Participants express differing views on whether the constant R is integrated or treated as a constant during the integration process. The discussion remains unresolved with multiple competing interpretations of the mathematical steps involved.

Contextual Notes

Some participants note the necessity of initial or boundary conditions to fix the integration constant, indicating that the integration process may depend on these conditions.

Peter Schles
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Dear Sirs,

I am currently calculating a velocity profile of an annular flow. Unfortunatelly I am not understanding the following step:

http://[url=https://postimg.org/image/vl256ffhj/][ATTACH=full]200119[/ATTACH]

That seems the author had integrated the R constant. And remains the question: why had R been realocated into the ln´s parenthesys?

Thanks,
Peter
 

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The first term R*r/R is obvious so I assume that your question regards the second term. Make a change of variables u = r/R, so that dr = R du. This R is pulled out in front making R^2, while int{du/u} becomes ln(u) = ln(r/R). There's no integration of constants.
 
No, he integrates rightly over ##r##. How do you come to a different conclusion. Note that
$$\frac{\mathrm{d}}{\mathrm{d} r} \ln(r/R)=\frac{1}{r}$$.
Rightly he avoids a dimensionful logarithm by introducing an arbitrary constant. You need initial/boundary conditions anyway to fix the integration constant ##C_2##. So that's the correct general solution of the ODE (2.4-5).
 
Hi, before the integration you can multiply and divide by ##R##, one of this remain outside the parentesis so the ##R^2##, after observe that ##\frac{1}{R}\left(\frac{R}{r}\right)## is ##\frac{d}{dr}\ln{\frac{r}{R}}##. Yes, here ##R## is trated as constant and ##C_{2}## is the constant of integration that remains multiplied by the constant term in front of the bracket.
 

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