Is the Electron Tunneling Probability Calculation Correct?

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The discussion focuses on calculating the electron tunneling probability for an electron with an incident energy of 8 eV encountering a barrier of height 13 eV and width 5 x 10-10 m. The relevant equation used is k = (sqrt(2m(V-E))/h, leading to a k value of 1.14 x 1010. The probability of tunneling is calculated using the formula e-2kL, resulting in a value of 11.2 x 10-6. However, it is emphasized that the comparison of the transmitted and incident wavefunctions is necessary for a complete understanding of the tunneling phenomenon.

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Discostu19
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assuming that the electron has an incident energy of 8eV and that the barrier is of height Vo=13eV and width L=5x10-10m calculate the probability that the electron will be able to tunnel through the barrier.Relevant equations= k = (sqrt(2m(V-E)) /h-answer

(sqrt(2x9.1x10-31(13-8)x1.6x10-19)x2pi all divided by h=(6.63x10-34)

giving 1.14x1010??

then using e-2kL = e-2x1.14x1010x5x10-10

=11.2x10-6

is this right :confused: ??
and wat would the final answer be after the 11.2x10-6
 
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Discostu19 said:
assuming that the electron has an incident energy of 8eV and that the barrier is of height Vo=13eV and width L=5x10-10m calculate the probability that the electron will be able to tunnel through the barrier.


Relevant equations= k = (sqrt(2m(V-E)) /h


-answer

(sqrt(2x9.1x10-31(13-8)x1.6x10-19)x2pi all divided by h=(6.63x10-34)

giving 1.14x1010??

then using e-2kL = e-2x1.14x1010x5x10-10

=11.2x10-6

is this right :confused: ??
No. You need to compare the transmitted piece of the wavefunction to the incident piece of the wave function. Have you studied "scattering" yet? This is a 1-D scattering problem.
 
erm i think we have yes
we've done a lot of electron tunnelling but not sure.
 

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