Is the Loss of Kinetic Energy Related to the Volume of a Copper Atom?

[Bolter]

Homework Statement

Work out the overall loss in kinetic energy

Relevant Equations

P=mv
PE = mgh
KE = 1/2mv^2

Unsure on whether I have done part d) right for this question

Here is what I have done already:

Any help would be great! Thanks

 

[haruspex]

I didn't understand your calculation in part c. You had 0.532 m/s for A's speed after impact, but it became 0.153 somehow.

 

[PeroK]

Homework Statement:: Work out the overall loss in kinetic energy
Homework Equations:: P=mv
PE = mgh
KE = 1/2mv^2

Unsure on whether I have done part d) right for this question

View attachment 254437

Here is what I have done already:

Any help would be great! Thanks

Looks okay to me.

What are your assumptions for part e)? Did you try googling for volume of copper atom?

 

[Bolter]

I didn't understand your calculation in part c. You had 0.532 m/s for A's speed after impact, but it became 0.153 somehow.

Sorry you are correct. A's speed after impact should have read 0.532 m/s. I don't know why but I misinterpreted it as 0.153 for some apparent reason

EDIT: my loss in KE still comes out to be the same as I remember punching in 0.532 m/s onto the calculator.

 

[Bolter]

Looks okay to me.

What are your assumptions for part e)? Did you try googling for volume of copper atom?

I have done a quick google search, and the atomic volume of copper comes out to be '1.182 x 10^-29 m^3' so both values are of the same magnitude roughly. For assumptions, I'm not too certain.