Is there a spectrum difference in amplitude modulation with a sine or cosine?

AI Thread Summary
Modulating a pulse X(t) with a sine wave results in a frequency spectrum expression that differs from that of a cosine wave, despite both being phase-shifted by π/2. The sine modulation yields a spectrum with components X(f-f0) and X(f+f0) having opposite phases, while the cosine modulation results in components with the same phase. This phase difference leads to a noticeable variation in the magnitude spectrum between the two modulations. The expectation that multiplying the cosine spectrum by e^{-jπ/2} would yield the sine spectrum is incorrect due to the distinct phase relationships of the components. Understanding these nuances is crucial for accurately interpreting the effects of modulation on the frequency spectrum.
DragonPetter
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If I modulate a pulse X(t) with a.) a sine wave or b.) a cosine wave, I have the frequency spectrum expressions
<br /> a.) \frac{1}{2j}[X(f-f_0)-X(f+f_0)]<br />
<br /> b.) \frac{1}{2}[X(f-f_0)+X(f+f_0)]<br />

When I plot these for a pulse, I see a difference in the magnitude spectrum, but I should not expect to see this since this is simply a phase shift of \pi/2

I would think if I multiplied b.) by e^{-j\pi/2}, I would get what I see in a.) but this is not the case.

Can anyone help me with what I'm missing?
 
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Ok, I'm guessing the phase shift e^-jpi/2 does not extract out so nicely as I thought for the a.) case when the sine Fourier transform is taken. The two components X(f-fo) and X(f+fo) will have opposite phases unlike in b.) so I cannot simply multiply b.) by a phase shift to get to a.)
 
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