Is this the right way to find Zeq for parallel circuit

AI Thread Summary
The discussion centers on finding the equivalent impedance (Zeq) for a parallel circuit involving a resistor and an inductor in series with a capacitor. The user initially calculates Zeq as 400Ω but questions whether the approach and the final value are correct. Feedback indicates that while the procedure is generally correct, the user needs to ensure proper units are included in their final answer. Additionally, there is confusion about how to apply the Vsource value in the equation provided. Clarification is given that the user ultimately arrives at the correct solution with assistance.
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Homework Statement


attachment.php?attachmentid=58319&stc=1&d=1367181165.jpg

http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/

Homework Equations



Vc=Vsource*Zeq/(200+Zeq)


The Attempt at a Solution



Is this the correct way to get Zeq
100Ω and inductor as series . so we
100+j100 parallel with the capacitor. which is -j100
so we use the formula Z1 + Z2//Z3
which we get 400

Is this correct
Also how do we multiply the Vsource value ?
 

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pokie_panda said:

Homework Statement


[PLAIN]http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/
http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/

Homework Equations



Vc=Vsource*Zeq/(200+Zeq)


The Attempt at a Solution



Is this the correct way to get Zeq
100Ω and inductor as series . so we
100+j100 parallel with the capacitor. which is -j100 \leftarrow should be -j200?
so we use the formula Z1 + Z2//Z3
which we get 400

Is this correct
Your description is a bit hard to follow, but it looks like you've got the right procedure. Your result has the correct magnitude, but lacks the appropriate units (that would lose you marks if submitted that way!).
Also how do we multiply the Vsource value ?
Multiply the Vsource? For what purpose?
 
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I ended up getting the correct solution , thanks for your help
 

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