Is (x+sqrt(2)) or (-x+sqrt(2)) rational?

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To prove that either (x + sqrt(2)) or (-x + sqrt(2)) is irrational for any real number x, the discussion begins with the established fact that sqrt(2) is irrational. The proof by contradiction assumes that one of the expressions is rational and sets (x + sqrt(2)) equal to a rational number m/n. The challenge arises in deriving a contradiction from this assumption, particularly in expressing x in terms of sqrt(2). The conversation concludes with the participant feeling they can proceed with the proof after clarifying their approach.
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Homework Statement



Prove that for each real number x, (x+sqrt(2)) is irrational or (-x+sqrt(2)) is irrational.


Homework Equations



We have already proven sqrt(2) is irrational
and a rational+an irrational=irrational.


The Attempt at a Solution



Proof by contradiction.

Assume (x+sqrt(2)) or (-x+sqrt(2)) is rational.

First set (x+sqrt(2))=(m/n) for some integers m and n.

I get stuck here at where to go with the contradiction.
 
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so say the positive sum is rational
x+sqrt{2} = \frac{p}{q} [\tex]<br /> <br /> then what is x? try using it to substitute into the negative sum
 
x=sqrt(2)

so...

2(sqrt(2))=(m/n)

I think I can take it from here. Thanks!
 
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