Is xn+yn a Cauchy sequence if xn and yn are Cauchy sequences?

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Homework Statement



Let xn and yn be Cauchy sequences.
Give a direct argument that xn+yn is a Cauchy sequence that does not use the Cauchy Criterion or the Algebraic Limit Theorem.

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The Attempt at a Solution


given epsilon>0 there exists an N in the natural numbers such that whenever m,n>N, it follows that:
\left|xn-xm\right|&lt;epsilon and \left|yn-ym\right|<epsilon
I'm not sure where to go next.
 
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To show that x_n + y_n is Cauchy, you want to prove that for any \epsilon &gt; 0 there is a natural number N such that if n, m &gt; N then |(x_n + y_n) - (x_m + y_m)| &lt; \epsilon, right?

Note that |(x_n + y_n) - (x_m + y_m)| = |(x_n - x_m) + (y_n - y_m)|. Now use the triangle inequality and remember that both sequences x_n, y_n are Cauchy.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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