Is {yn} a Cauchy Sequence if {xn} Is?

bloynoys
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Homework Statement



Prove the following assertion: Suppose {xn} and {yn} are Cauchy sequences of real number. If {xn} is a cauchy sequence and for every η>0 there exists a pos. int. N such that for every n>N so that abs(xn-yn)<η then {yn} is a Cauchy sequence.


Homework Equations


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The Attempt at a Solution


We will prove that {yn} is a cauchy sequence by showing that for every ε>0 there exists a pos. int. N so that both n and m >N so that abs(yn-ym)<ε.

Consider ε>0 arbitrary.
Since {xn} is a cauchy sequence and by hypothesis for every η>0 there exists an N so that every n>N abs(xn-yn)<η. Choose such an N.
Consider n,m>N arbitrary.

Then I know I need to get from abs(yn-ym) to ε but unsure how to use what I have to get there correctly and if I have the rest of the proof right.
 
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bloynoys said:

Homework Statement



Prove the following assertion: Suppose {xn} and {yn} are Cauchy sequences of real number. If {xn} is a cauchy sequence and for every η>0 there exists a pos. int. N such that for every n>N so that abs(xn-yn)<η then {yn} is a Cauchy sequence.


Homework Equations


None



The Attempt at a Solution


We will prove that {yn} is a cauchy sequence by showing that for every ε>0 there exists a pos. int. N so that both n and m >N so that abs(yn-ym)<ε.

Consider ε>0 arbitrary.
Since {xn} is a cauchy sequence and by hypothesis for every η>0 there exists an N so that every n>N abs(xn-yn)<η. Choose such an N.
Consider n,m>N arbitrary.

Then I know I need to get from abs(yn-ym) to ε but unsure how to use what I have to get there correctly and if I have the rest of the proof right.

Use the Cauchy sequence {xn} as your bridge, think about triangle inequality, also note that η may be set according to ε
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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