- #1
yankees26an
- 36
- 0
NVM I solved it. Thanks for reading anyway :)
610 J of heat is added to 3.4 mol of a monatomic ideal gas at constant pressure. Find the
change of temperature of the gas.
At isobaric conditions, w = p[tex]\Delta[/tex]V = nR[tex]\Delta[/tex]T
w = nR[tex]\Delta[/tex]T
w = 610 J; n = 3.4
610/(3.4*8.314) = 21.5 K = [tex]\Delta[/tex]T
Calculations look right to me,but the answer is 8.63 K
Homework Statement
610 J of heat is added to 3.4 mol of a monatomic ideal gas at constant pressure. Find the
change of temperature of the gas.
Homework Equations
At isobaric conditions, w = p[tex]\Delta[/tex]V = nR[tex]\Delta[/tex]T
w = nR[tex]\Delta[/tex]T
The Attempt at a Solution
w = 610 J; n = 3.4
610/(3.4*8.314) = 21.5 K = [tex]\Delta[/tex]T
Calculations look right to me,but the answer is 8.63 K
Last edited: