bjnartowt
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Homework Statement
With a Taylor series expansion of the well-behaved \rho ({\bf{x'}}) around {\bf{x'}} = {\bf{x}}, one finds the Taylor expansion of the charge density to be,
\rho ({\bf{x'}}) = \rho ({\bf{x}}) + {\textstyle{1 \over 6}}{r^2}{\nabla ^2}\rho + ...
Homework Equations
The Attempt at a Solution
This proposed Taylor exapnsion looks correct, except for the 1/6 instead of the 1/2. What gives??