Jacobian Determinant/ mult. variable implicit differentiation

Isaac Wiebe
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Homework Statement


Let F: x^2 + y^2 - z^2 + 2xy - 1 = 0 and G: x^3 + y^3 - 5y - 4 = 0. Calculate dz/dx. Note: This is NOT the partial derivative ∂z/∂x.

I do not need help in taking the derivative of many polynomials. What I need help in is setting up a Jacobian determinant to evaluate this.


Homework Equations



The Jacobian determinant, bit tough to explain in a short period of space. Exceptionally helpful with many equations with as many variables as equations, in which the partial derivative can be evaluated by the Jacobian Determinant.



The Attempt at a Solution


Okay, so dz/dx = [∂(F, G) /∂(z, y)] / ∂(F, G) / ∂(x, y) * (-1), but this is incorrect as this is ∂z/∂y. Essentially I need to know, what is a function of what, and how can I evaluate this? I do not care necessarily for the answer, simply for the setup.
 
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The ultimate independent variable is x. G relates x and y so y is only function of x:y=y(x).
F is a relation among x, y, z. z depends both on y and x: z=z(x,y(x)). ehild
 
Here is the motivation
F(x,y,z)=0
G(x,y,z)=0
0=dF=Fx dx+Fy dy+Fz dz
0=dG=Gx dx+Gy dy+Gz dz
first we find
0=(Gy dF - Fy dG)/dx
which will have the Jacobians you seek
then think it through in general

What happens is you get F,G,x,y in one Jacobian and F,G,y,z in the other and F,G,y effectively cancel (chain rule) leaving dz/dx
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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