Just can't seem to get this one

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To solve the projectile motion problem of a third baseman throwing a ball, it's essential to analyze the horizontal and vertical components separately. The ball is thrown horizontally at a speed of 38.0 m/s from a height of 1.20 m, and the distance to first base is 39.0 m. The time it takes for the ball to hit the ground can be calculated using the vertical motion equations, while the horizontal distance can be determined using the horizontal speed. Additionally, to find the angle for a throw that reaches the first baseman at the same height, projectile motion equations must be applied. Understanding these components is crucial for solving the problem effectively.
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A third baseman makes a throw to first base 39.0 m away. If the ball leaves his hand traveling horizontally with a speed of 38.0 m/s at a height of 1.20 m from the ground, how far will it go before striking the ground? At what angle must he throw the ball so that it reaches the first baseman’s glove at a height of 1.20 m above the ground.?
 
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What have you done with it so far?
 
Maybe give him a formula... I would but I don't know it.

Paden Roder
 
Whenever you encounter a projectiles problem, remember to treat the vertical and horizontal components of the motion of a projectile separately. Tide is right: tell us what you've done and we'll go from there.
 

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