K Physics: How much work is done by friction on a sliding block?

AI Thread Summary
The discussion focuses on calculating the work done by friction on a 2.3-kg block sliding down a 43-degree inclined plane at a constant speed of 3.3 m/s. It emphasizes that the power, or rate of doing work, is related to both the frictional force and the block's velocity. Since the block moves at a constant speed, the frictional force can be determined, and the work done by friction is negative due to its opposing direction to the block's displacement. Understanding the relationship between power and velocity is crucial for solving the problem. The key takeaway is that the work done by friction is calculated as a negative value due to its opposing nature.
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A 2.3-kg block slides down a plane (inclined at 43degrees with the horizontal) at a constant speed of 3.3 m/s. At what rate is the frictional force doing work on the block?
 
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The rate of doing work is just the power. Do you know an expression relating power and velocity? You'll also need the frictional force, but you should be able to get it because you're told that the block is traveling at a constant speed..
 
..and also the work done will be negative , since the direction of the frictional force is opposite to the displacement direction.

BJ
 
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