- #1
jjones1573
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Homework Statement
A particle leaves a ledge at a height of 4m and hits the ground at 1.2s later landing 2m away horizontally.
find:
The original velocity
The final velocity
The max height acheived
Homework Equations
So I know that for the original velocity:
Vo = D * SQRT(g/2H)
where:
Vo = original velocity
D = how far it landed
g = gravity
H = original height
The Attempt at a Solution
So for my initial velocity with the above equation I get:
Vo = 2 * SQRT( 9.8 / 2 * 4)
= 2.1m/s
Is this method correct?
I'm not sure how to find the final velocity before it hits the ground
Also the max height is surely the original height of 4m as its going down from here. suppose the particle jumped from its position on the ledge could I figure out a max height.
One last thing. could anybody show me how to find an acceleration vector of a projectile. I know how to get the velocity vector using arctangent but I can't find anything on acceleration vectors.
thanks so much,