How Far Will a Puck Slide with Friction?

AI Thread Summary
A puck with an initial velocity of 7.5 m/s experiences a frictional force of 3.2 N while sliding on a horizontal surface. The calculations indicate that the puck will travel approximately 9.7 meters before coming to a stop. The initial attempt at solving the problem incorrectly applied constant velocity equations, leading to an overestimation of distance. The correct approach involves using the deceleration caused by friction to determine the stopping distance. Properly applying the equations of motion is essential for accurate results in physics problems.
Anuj Agarwal
Messages
2
Reaction score
0

Homework Statement


A force of friction of 3.2N acts on a 1.1Kg puck while it is sliding along a horizontal surface. If the initial velocity of the puck was 7.5 m/s, how far will the puck travel before coming to rest?

Homework Equations

The Attempt at a Solution


The answer is 9.7M. Tried multiple time with different formulas but unable to derive at solution.
 
Physics news on Phys.org
Hi @Anuj Agarwal, Welcome to Physics Forums.

You need to show us at least one of your attempts in detail or your thread will be deleted. Just saying you tried and failed does not give us any basis upon which to help you.
 
Sorry. Here is my try: F =mxa hence a = f/m=3.2/1.1=2.9
A=v/s, hence s=v/a =7.5/2.9=2.58
Distance = velocityxtime = 7.5x2.58=19.3 m
 
The last line is wrong. This would only be true if the velocity were constant. The fact that your answer is twice as big as it should be should give you a clue.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

How to find the coefficient of kinetic friction
Replies
4
Views
3K
Using the angular momentum principle for 2 pucks
Replies
3
Views
2K
Conservation of Work/Momentum of Puck Sliding Off Plate
Replies
4
Views
2K
Complex Kinematics and Dynamics
Replies
8
Views
2K
Complex Kinematics and Dynamics
Replies
7
Views
2K
A puck is sliding on flat ground with an intial speed
Replies
2
Views
1K
Hockey Puck Collision--momentum problem
Replies
2
Views
4K
Energy Conservation: Puck on Wood on Frictionless Surface
Replies
14
Views
2K
Why Does Kinetic Energy Seem Lost in a Collision Despite No Friction?
Replies
7
Views
2K
Frictional Forces-finding velocity and distance
Replies
4
Views
3K

Hot Threads

Recent Insights

Back
Top