Kinetics with Veloctiy/Acceleration Problem

  • Thread starter Thread starter azn1x6flame
  • Start date Start date
  • Tags Tags
    Kinetics
AI Thread Summary
The discussion revolves around solving a velocity function v(t) = 3t - 11 for a particle's distance traveled over the interval from t = 0 to t = 5 seconds. The user initially calculates the velocity at t = 5 but realizes this does not represent the total distance traveled. They attempt to find the anti-derivative of the velocity function to calculate distance but encounter issues with their integration, leading to a negative result. The user is confused about the correct approach and how to properly evaluate the integral, as their answer differs from the one provided in the answer book. Clarification on integrating polynomials and evaluating definite integrals is needed to resolve the discrepancies.
azn1x6flame
Messages
3
Reaction score
0
Hello, I need help on this following problem on velocity/acceleration

1. Homework Statement

The velocity function (in meters per second) is given for a particle moving along a line.

v(t)=3t-11, 0 (greater than or equal to) t (greater than or equal to) 5

Find the distance (in meters) traveled by the particle during the given time interval2. Homework Equations

v(t)=3t-11, 0 (greater than or equal to) t (greater than or equal to) 5

3. The Attempt at a Solution

I tried the following:
3(5)-11=4

But it isn't correct, can someone help me with this problem?

I know I have to find the anti-derivative of v(t).

How would I find t? Do I have to do the derivative of v(t) to find acceleration? Would that help me do this problem?

Can someone help me with this problem?

Thanks
 
Physics news on Phys.org
I tried the following:
3(5)-11=4

That's the velocity of the particle at t=5. It's not the total distance travelled.

I know I have to find the anti-derivative of v(t).

How would I find t? Do I have to do the derivative of v(t) to find acceleration? Would that help me do this problem?

The anti-derivative is just the integral. Do you know how to find the integral of a polynomial?
 
ideasrule said:
That's the velocity of the particle at t=5. It's not the total distance travelled.
The anti-derivative is just the integral. Do you know how to find the integral of a polynomial?

Yes. This is what I have so far and it's coming up negative:

3/2*t^2-11*t from 0 to 5, so 3/2*25-55 -0 = 125/2-55=-17.5

Whereas the answer book is showing: 137/6

So for some reason, my answer isn't totaling correctly
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top