Kirchhoff's Rules and Systems of Equations

AI Thread Summary
The discussion focuses on solving a circuit problem involving Kirchhoff's Rules and systems of equations for a series/parallel circuit. The circuit includes resistors R1, R2, and R3, with a battery voltage of 2.62 volts. The user attempted to derive equations for the currents using Kirchhoff's laws but encountered discrepancies between their calculated values and the measured currents. A key error was identified in the manipulation of the equations, specifically in dividing terms incorrectly. The user seeks clarification on where their calculations went wrong to align their results with the measured data.
succubus
Messages
33
Reaction score
0

Homework Statement


To find the current traveling through a circuit with parallel and series connections. The circuit looks something like this.

*Right now my webserver is giving me fits and won't let me login. I will try and get a picture to those who cannot understand what I am about to describe below, and with my poor description skills, will probably be everyone.

It's a series/parallel circuit. First there is R1(97.8), and then the circuit splits into parallel with R3(553) on the outside and R2(325) on the inside, and then continues around to a battery that has a measured voltage of 2.62 volts.

We measured the current in the lab, so we have the answers. The problem is, were supposed to use systems of equations to discover the answer as if we didn't measure it. IO have tried my best to do something about, and these are the equations I have come up with (we were only told to use 3, not the 4th for the inner current) and tried solving for each individual variable to no avail. This is what I've done.

Homework Equations



Outer current
(1) V-R1I1 - R3I3 = 0
Parallel Loop Current (Inside parallel circuit from R3 to R2)
(2) -R3I3 + R2I2 = 0
Junction Rule
(3) I1 = I2 +I3

I'm pretty sure my equations are correct.

I substituted I1 in equation 3 into equation 1 to get

V-R1(I2 + I3) - R3I3 = 0
Then I solved for I2
-R1I2 - R1I3 - R3I3 = -V
-R1I2 - I3(R1 + R3) = -V
-V + I3(R1 + R3) = -R1I2
(Divide by R1)

-V + I3(R3) = - I2

I2 = V - R3I3

Then I substituted what I got for I2 into equation 2

-R3I3 + R2(V-R3I3) = 0

-R3I3 - R2V - R2R3I3 = 0

-R3I3 - R2R3I3 = R2V

-I3(R3 + R2R3) = R2V
Divide by R3 + R2R3 yields

-I3 = V/2R3

which gives me something similar to the current I measured for I3, but 1 decimal off.

Measured currents are below

I1 = 7.43 mA
I2 = 24.3 mA
I3 = 24 mAWhere did I go wrong? When I plug in the answers they don't come anywhere close to what I measured across the circuit. I'm pretty sure we measured the current correctly. :/
 
Last edited:
Physics news on Phys.org
succubus said:

Homework Statement


To find the current traveling through a circuit with parallel and series connections. The circuit looks something like this.

*Right now my webserver is giving me fits and won't let me login. I will try and get a picture to those who cannot understand what I am about to describe below, and with my poor description skills, will probably be everyone.

It's a series/parallel circuit. First there is R1(97.8), and then the circuit splits into parallel with R3(553) on the outside and R2(325) on the inside, and then continues around to a battery that has a measured voltage of 2.62 volts.

We measured the current in the lab, so we have the answers. The problem is, were supposed to use systems of equations to discover the answer as if we didn't measure it. IO have tried my best to do something about, and these are the equations I have come up with (we were only told to use 3, not the 4th for the inner current) and tried solving for each individual variable to no avail. This is what I've done.

Homework Equations



Outer current
(1) V-R1I1 - R3I3 = 0
Parallel Loop Current (Inside parallel circuit from R3 to R2)
(2) -R3I3 + R2I2 = 0
Junction Rule
(3) I1 = I2 +I3

I'm pretty sure my equations are correct.

I substituted I1 in equation 3 into equation 1 to get

V-R1(I2 + I3) - R3I3 = 0
Then I solved for I2
-R1I2 - R1I3 - R3I3 = -V
-R1I2 - I3(R1 + R3) = -V
-V + I3(R1 + R3) = -R1I2
(Divide by R1)

-V + I3(R3) = - I2

I2 = V - R3I3

Then I substituted what I got for I2 into equation 2

-R3I3 + R2(V-R3I3) = 0

-R3I3 - R2V - R2R3I3 = 0

-R3I3 - R2R3I3 = R2V

-I3(R3 + R2R3) = R2V
Divide by R3 + R2R3 yields

-I3 = V/2R3

which gives me something similar to the current I measured for I3, but 1 decimal off.

Measured currents are below

I1 = 7.43 mA
I2 = 24.3 mA
I3 = 24 mA


Where did I go wrong? When I plug in the answers they don't come anywhere close to what I measured across the circuit. I'm pretty sure we measured the current correctly. :/

You went wrong here:
-V + I3(R1 + R3) = -R1I2
(Divide by R1)

-V + I3(R3) = - I2

R1 + R3 divided by R1 is not R3.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top