Laplace's Transform: Initial-value Theorem applied to the n-th derivative

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SUMMARY

The discussion centers on applying the initial-value theorem of Laplace's Transform to the n-th derivative, specifically proving that lims tends to infinity sn+1F(s) = f(n)(0+). The user successfully applies the theorem for the first derivative under the assumption of continuity and exponential order. However, they seek clarification on whether to assume that all initial values except for f(n)(0+) are zero when dealing with higher derivatives.

PREREQUISITES
  • Understanding of Laplace Transform and its properties
  • Familiarity with the initial-value theorem
  • Knowledge of derivatives and their notation
  • Concept of functions of exponential order
NEXT STEPS
  • Study the implications of the initial-value theorem in Laplace Transforms
  • Research the conditions for continuity and exponential order in functions
  • Explore higher-order derivatives and their Laplace Transforms
  • Learn about the behavior of Laplace Transforms as s approaches infinity
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Students and professionals in mathematics, engineering, and physics who are working with differential equations and Laplace Transforms, particularly those focusing on initial-value problems and higher-order derivatives.

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Homework Statement



Prove that, under the right assumptions, lims tends to infinity sn+1F(s) = f(n)(0+)

The Attempt at a Solution



I don't have a problem with the common initial-value theorem, under the assumptions that both f and f' are partly continuous and of exponential order. Then I can find that the absolute value of sF(s) tends to f(0+).

But for f(n)(t), the Laplace's transform is sn+1F(s) - [snf(0+) + sn-1f'(0+) + ... + f(n)(0+)].

Should I make the assumption that all initial values except for f(n)(0+) are equal to zero?
 
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