Laws of motion/vectors question?

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A 10 kg block is acted upon by two forces, resulting in a question about calculating the magnitude of the resultant acceleration. The forces are given as (10i + 20j) N and (6i - 8j) N. To find the resultant force, the horizontal and vertical components must be added, yielding a resultant vector of (16i + 12j) N. Using the formula F=ma, the magnitude of the resultant force is calculated, leading to the correct acceleration value. The discussion concludes with the participant successfully determining the answer.
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1. Homework Statement

A 10 kg block is subjected to two forces (10i + 20j) N and (6i - 8j) N. The magnitude of the resultant acceleration is

(a) 2 (b) 3 (c) 4 (c) 5


2. Homework Equations

F=ma


3. The Attempt at a Solution

I was thinking maybe I should add the horizontal components to get the force acting horizontally, and then substitute that and the mass into F=ma to get 'a', but that way I get 1.6 m/s^2 which isn't even an option. Someone help, please?

 
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What about the vertical components?

ehild
 
Yes, I don't know how I'm supposed to take them into account. I thought there's no need to. :S Tell me how to start?
 
ooohlala said:
Yes, I don't know how I'm supposed to take them into account. I thought there's no need to. :S Tell me how to start?

You have learned vector addition. The resultant of two vectors added is a new vector. All vectors have components. How do you get the components of the resultant vector?

ehild
 
By adding 10 to 6 and 20 to -8 to get (16i + 12j)?
 
Yes. Now you have F=ma. The acceleration is vector, and it points at the same direction as F. Therefore its magnitude is proportional to the magnitude of the force. You have to find the magnitude or the force first. How do you get the length (magnitude) of a vector?

ehild
 
Haha thank you, I got the answer. :)
 
ooohlala said:
Haha thank you, I got the answer. :)

Congratulation! :smile:

ehild
 
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