LC Circtuit finding Q across an element for given time

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The discussion revolves around solving a circuit problem involving two capacitors and an inductor, with specific values provided for each component. The user is attempting to find the charge on capacitor C1 at a given time (t1 = 14.6 ms) and the voltage across the inductor at that same time. They have calculated the angular frequency and attempted to derive the charge using the equations for current and charge in an LC circuit, but their results are incorrect. The user expresses frustration over not being able to solve the problem for a week and seeks assistance. The circuit configuration is confirmed to be in series, and the user acknowledges a mistake in not including a diagram.
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Homework Statement


A circuit is constructed with two capacitors and an inductor as shown. The values for the capacitors are: C1 = 513.0 μF and C2 = 68.0 μF. The inductance is L = 265.0 mH. At time t =0, the current through the inductor has its maximum value IL(0) = 106.0 mA and it has the direction shown.

2) What is Q1(t1), the charge on the capacitor C1 at time t = t1 = 14.6 ms? The sign of Q1 is defined to be the sameas the sign of the potential difference Vab = Va - Vb at time t = t1.

3) What is Vbc(t1)= Vb - Vc, the voltage across the inductor at time t1 = 14.6 ms? Note that this voltage is a signed number.


Homework Equations



w0 = 1/sqrt(LC)
I(t) = -wQmax*sin(wt+phi)
Q(t) = Qmax*cos(wt+phi)

The Attempt at a Solution


can't solve this for a week...

plugging in given... w = 250,
I(0) = I max = .106 = -wQ(1)
so Qmax = 4.24E-4
Also, sin(wt+phi) = 1 @ t=0, so w(0)+phi = pi/2
phi=pi/2.

for t=.0146s,
Q(.0146) = Qmax*cos(wt+phi)...
plugged into get 2.0639E-4, but it's wrong...



As for 3, once i solve for Q in question 2, i can use that in Q/C = Vinductor...
 
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The circuit is not shown.
 
Woops, meant to mention the 3 elements (2 capacitors and the inductor) are just in series so no diagram was needed.

It prob happened since I exited this once as I was typing the question, so forgot to do so second time around D:

and I STILL need help on this
 

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