Learn How to Simplify Algebraic Expressions with Easy Tips and Tricks

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The discussion revolves around simplifying the expression involving fractions and algebraic terms. The main confusion arises from whether to treat "x + 1 - x + 1" as a simple subtraction or as a more complex operation involving fractions. Clarification is provided that the expression should be treated as a fraction, leading to the conclusion that the result simplifies to x. Ultimately, the correct approach involves handling the fractions first before performing the subtraction, resulting in the final answer. Understanding the order of operations is crucial for arriving at the correct solution.
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Question:
1
_________
x + 1 - x + 1
_______
1
____
x+1

Here's where I'm stuck:

x + 1 * x+1
____
1

= x^2 + 2x + 1

(x + 1) - (x^2 + 2x + 1)

How are you supposed to deal with the x + 1 - x + 1
Thanks?
 
Last edited:
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What are you trying to get at here?, are you trying to find a derivative using the first principles?
 
The question is supposed to be simplified as a fraction in lowest terms - or not a fraction if that is the case. I don't know what your referring to I'm afraid, my math rhetoric is fairly limited.
 
well, okay, is it x+1-x+1 OR (x+1)-(x+1), because if it has brackets then it would equal 0, but if it has no brackets then it would simplify to 2.
 
I'm not sure excatly what you're trying to do but surely x + 1 - x + 1 = 2

simulpost :blushing:
 
Last edited:
The lines represent fractions or division. The x + 1 is being (-) subtracted by a fraction, which is connected to a bunch of other fractions. I how to get common denominators however once.

--- does not equal division or anything --- was used for moving #'s over.

------- 1
-------___
x + 1 - x+1
------- ___
------- 1
------- ___
------- x+1

I'm not sure what to do from there.
 
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You'll have to be clearer, but surely 1/(x+1)/1/(x+1) = 1
 
I've got it now, thanks. The result of all the fractions is done first, then subtracted from x + 1, which gives you x, which results in the correct answer as marked on the sheet.

Thanks again.
 
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